bounded function वाक्य
उदाहरण वाक्य
मोबाइल
- Rather, a bounded linear operator is a locally bounded function.
- Interpreted na�vely, the Hilbert transform of a bounded function is clearly ill-defined.
- For any bounded function " F " on the random trajectories of the signal.
- A continuous bounded function on a finite interval of the real numbers will also have a minimum.
- When the approximation equation ( ) is satisfied for any bounded function " f " we write
- A bounded function that is holomorphic in the entire complex plane must be constant; this is algebraically closed.
- Compare this with a bounded function, for which the constant does not depend on " x ".
- The association of a bounded harmonic function to an ( essentially ) bounded function on the boundary is one-to-one.
- If so, then they are both integrable because the integral of a bounded function on a set of finite measure is definitely finite.
- The induced operator is bounded if and only if the coefficients of the Toeplitz matrix A are the Fourier coefficients of some essentially bounded function f.
- Furthermore, every bounded function on a closed bounded interval has a Lebesgue integral and there are many functions with a Lebesgue integral that have no Riemann integral.
- Since it is defined as convolution with a bounded function, it is a bounded operator on L 2 ( "'T "').
- Contents give a good notion of integrating bounded functions on a space but can behave badly when integrating unbounded functions, while measures give a good notion of integrating unbounded functions.
- In mathematical analysis, the "'uniform complex-valued bounded functions " f " defined on a set " S " the non-negative number
- A powerful property of G-networks is that they are universal approximators for continuous and bounded functions, so that they can be used to approximate quite general input-output behaviours.
- This can also be deduced directly because, after passing to Fourier transforms, " H " ? and " H " become multiplication operators by uniformly bounded functions.
- A concrete realization of the * homomorphisms in " X " as " K "-biinvariant uniformly bounded functions on " G " is obtained as follows.
- Implicit in the definition of a Riemann integral is that the value of the integral is finite since the function must be a bounded function and the integral must be on a closed interval?
- The title of his doctoral thesis was " �ber das Koeffizientenproblem der beschr�nkten Funktionen von zwei Ver�nderlichen " ( " On the coefficient problem of the bounded functions of two variables " ).
- In particular, any set that is at most countable has Lebesgue measure zero, and thus a bounded function ( on a compact interval ) with only finitely or countably many discontinuities is Riemann integrable.
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