This sequence ends at \ mathrm { _ { 28 } ^ { 56 } Ni } because it is the most stable ( i . e ., it has the highest nuclear binding energy per nucleon ).
32.
As nucleons are added, the total nuclear binding energy always increases but the total disruptive energy of electric forces ( positive protons repelling other protons ) also increases, and past iron, the second increase outweighs the first.
33.
:: The nuclear analogy for bond dissociation energy ( which can be used to calculate the enthalpy of chemical reactions ) is nuclear binding energy-- " 32 " 20 : 32, 31 August 2016 ( UTC)
34.
Nickel-62, a relatively rare isotope of nickel, has a higher nuclear binding energy per nucleon; this is consistent with having a higher mass per nucleon because nickel-62 has a greater proportion of neutrons, which are slightly more massive than protons.
35.
The assumption of nucleus as a drop of Fermi liquid is still widely used in the form of Finite Range Droplet Model ( FRDM ), due to the possible good reproduction of nuclear binding energy on the whole chart, with the necessary accuracy for predictions of unknown nuclei.
36.
The modern version of Prout's rule is that the atomic mass of an isotope of proton number ( atomic number ) " Z " and neutron number " N " is equal to sum of the masses of its constituent protons and neutrons, minus the mass of the nuclear binding energy, the mass defect.
37.
In general, the mass number of a given nuclide differs in value slightly from its atomic mass, since the mass of each proton and neutron is not exactly 1 " u "; since the electrons contribute a lesser share to the atomic mass as neutron number exceeds proton number; and ( finally ) because of the nuclear binding energy.
38.
Mass energy equivalence tells me that nuclear binding energy is found by measuring atomic mass and subtracting the AMUs for the protons and neutrons, Atomic mass tells me that it's done with mass spectrometry, and Mass spectrometry tells me a lot of things about the process, but as far as I can see, it doesn't tell me how it works.
39.
Such reactions are not driven by changes in binding energies as calculated from previously fixed " N " and " Z " numbers of neutrons and protons, but rather in decreases in the total mass of the nuclide / per nucleon, with the reaction . ( Note that the Binding Energy given above for hydrogen-1 is the atomic binding energy, not the nuclear binding energy which would be zero .)
