In circumstances of constant acceleration, these simpler equations of motion are usually referred to as the " SUVAT " equations, arising from the definitions of kinematic quantities : displacement ( ), initial velocity ( ), final velocity ( ), acceleration ( ), and time ( ) . ( see below)
42.
Now the " acceleration " of the electron will depend on the potential gradient which does depend on the distance between the plates-but you are not asked to find any details of the motion of the electron as it travels between the plates-you are only asked for its final velocity.
43.
Mathematically, the velocity with which it would hit the ground would look something like : v = u-( ( 2Du + 2Dd ) / 2 ) ?where v is the final velocity, u is the initial velocity and D u and D d are the energy losses on the ascent and decent respectively.
44.
And, though I do not have figures for StuRat, the fuel required to lift the fuel means that a normal rocket launch is pretty much exponentially costly in the final velocity required, a problem that does not exist for the launcher-based launch . Quondum 04 : 10, 13 July 2014 ( UTC)
45.
So if a spacecraft is on a parabolic flyby of Jupiter with a periapsis velocity of 50 km / s, and it performs a 5 km / s burn, it turns out that the final velocity change at great distance is 22.9 km / s; giving a multiplication of the burn by 4.6 times.
46.
I haven't had access to MATLAB to try to compute the roots in a sane manner yet ( c is hard to run through online calculators, but substituting 3 for c says that v only has one real solution ), but already the final velocity of the mirror is not dependent on E1 or the mass of the mirror.
47.
If that's indeed the case, than the solution is really trivial . use the second equation to express one of the final velocities in terms of the other and substitute it on the first equation, which will then have only one unknown and will be easy to solve . talk ) 23 : 20, 25 April 2011 ( UTC)
48.
If the hight of the fall began at the minimum fatal distance than we would expect our the tethered adventurer to survive, however from a height of X time that minimum deadly height ( and here the OP should do his homework, the means to work out a solution were given in some of these replies ) the final velocity would be deadly.
49.
If in that time your hands moved 3 degrees from rest, and assuming your arm's length is also 50cm, it moved 2.6cm in less than 1 / 300 s, which means a mean speed of 7.85m / s and assuming a linear acceleration, the final velocity would be double that, or 15.7m / s.
50.
The relationship is described by the " rocket equation " : V _ f = V _ e \ ln ( M _ 0 / M _ f ), where V _ f is the final velocity, V _ e is the exhaust velocity relative to the rocket, M _ 0 is the initial total mass, and M _ f is the mass after the propellant is burned.
