Would the value of 6 Bohr magnetons be a good ( order of magnitude ) approximation?
2.
The intrinsic electron magnetic dipole moment is approximately equal to the Bohr magneton " ?"
3.
Particles with spin have a corresponding spin magnetic moment quantized in units of, the Bohr magneton:
4.
One can note that g \ sqrt { J ( J + 1 ) } is the effective number of Bohr magnetons.
5.
Electrons orbiting around the nucleus in a current loop create a magnetic field which depends on the Bohr Magneton and magnetic quantum number.
6.
The Bohr magneton, which is calculated in the same fashion as the nuclear magneton, is larger than " & mu;"
7.
Where is the total angular momentum quantum number, is the Land?" g "-factor, and is the Bohr magneton.
8.
I'm currently trying to calculate the dimensionless Bohr Magneton number p eff for CuSO 4 ?H 2 O . The formulae I have are:
9.
Because the value for the magnetic moment is inversely proportional to particle mass, the nuclear magneton is about 1 / 2000 as large as the Bohr magneton.
10.
Since an electron's spin magnetic moment is constant ( approximately the Bohr magneton ), then the electron must have gained or lost angular momentum through spin orbit coupling.
