| 1. | The distribution of the shear stress is described by the Carter-Fromm solution.
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| 2. | These definitions are consistent with those of normal stress and shear stress.
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| 3. | Further, the rupture will occur in an area of greatest shear stress.
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| 4. | The shear stress can be further decomposed into two mutually perpendicular vectors.
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| 5. | Solids can be subjected to shear stresses, and to normal stresses both tensile.
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| 6. | Specifically, perfect fluids have no shear stresses, viscosity, or heat conduction.
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| 7. | Continued weakening may result in partial melting along zones of maximal shear stress.
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| 8. | The resulting intensity of the shear stress causes a breakage along the faces.
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| 9. | The apparent shear rate, the shear stress, and the apparent viscosity are calculated:
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| 10. | There are several ways to solve for the bed shear stress.
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