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compton wavelength वाक्य

"compton wavelength" हिंदी मेंcompton wavelength in a sentence
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  • In the above equation, the effect of the reduced mass is achieved by using the increased Compton wavelength, which is just the Compton wavelengths of the electron and the proton added together.
  • In the above equation, the effect of the reduced mass is achieved by using the increased Compton wavelength, which is just the Compton wavelengths of the electron and the proton added together.
  • I believe also that the Compton wavelength is always the smaller of the two ( if we consider the particle's relativistic mass in defining it, which I believe is appropriate ).
  • Where \ alpha \ approx 1 / 137 is the fine structure constant, and \ hbar / m _ { \ mathrm { e } } c is the Compton wavelength of the electron.
  • If Planck length is the minimum then either a body's reduced Compton wavelength or its half gravitational radius is a physical impossibility since one of these must be smaller than the Planck length.
  • Thus the magnitude of the shift is related not to the Compton wavelength of the electron, but to the Compton wavelength of the entire atom, which can be upwards of 10 000 times smaller.
  • Thus the magnitude of the shift is related not to the Compton wavelength of the electron, but to the Compton wavelength of the entire atom, which can be upwards of 10 000 times smaller.
  • Since the M�ller radius is of the order of the Compton wavelength of the isolated system, it is impossible to explore its interior without producing pairs, namely without taking into account relativistic quantum mechanics.
  • Thus the magnitude of the shift is related not to the Compton wavelength of the electron, but to the Compton wavelength of the entire atom, which can be upwards of 10, 000 times smaller.
  • Thus the magnitude of the shift is related not to the Compton wavelength of the electron, but to the Compton wavelength of the entire atom, which can be upwards of 10, 000 times smaller.
  • This value is a dimensionless quantity formed by the ratio of two energies : the electrostatic energy of attraction ( or repulsion ) at a separation of one Compton wavelength, and the rest energy of the charge.
  • You can do that using the formula for the Compton wavelength lambda = hbar / ( mc ) which is, of course, the same as 1 / m if you put hbar = c = 1.
  • Where f _ 0-frequency of the polarized radiation falling on the polarizer, f-frequency of the radiation passes through polarizer, \ lambda-Compton wavelength of electron, c-speed of light in vacuum.
  • This is simplified by assuming that the electron and neutrino eigenfunctions \ psi _ s and \ phi _ \ sigma are constant within the nucleus ( i . e ., their Compton wavelength is much smaller than the size of the nucleus ).
  • :: : : Although it works a bit differently than with a proton, elementary particles do sort of have a radius, in that it becomes rather meaningless to talk about a particle's position to a precision smaller than its Compton wavelength.
  • The observations of the inspiral give an upper limit on the mass of the graviton of, corresponding to or a Compton wavelength ( " "'? g " "') of greater than km, roughly 1 light-year.
  • Well, barring those other possibilities, we'd have to change the size of the atoms themselves, i . e . change the Compton wavelength of the electron-the electron mass, or the base speed of light in vacuum, I think.
  • The trouble was worse in classical field theory than in quantum field theory, because in quantum field theory a charged particle experiences Zitterbewegung due to interference with virtual particle-antiparticle pairs, thus effectively smearing out the charge over a region comparable to the Compton wavelength.
  • Proposals that may lead to a quantum theory of gravity such as string theory and loop quantum gravity predict violations of the weak equivalence principle because they contain many light scalar fields with long Compton wavelengths, which should generate fifth forces and variation of the fundamental constants.
  • The Planck mass m _ { \ rm P } = \ sqrt { \ hbar c / G } is special because the Compton wavelength and the Schwarzschild radius r _ { \ rm S } = 2 G M / c ^ 2 for this mass are of the same order.
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